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`a^(2) + b^(2) + 9c^(2) = 25``a + b + c gt 0``a^(2) + b^(2) + c^(2) = 17``a + b + c lt 0`

Answer :

A::C::DSolution :

`(2^((4)/(x)))/(2^(x+3))gt1` <br> `2^((4)/(x)-x-3)gt1` <br> `(4)/(x)-x-3gt0`<br> `(4-x^(2)-3x)/(x)gt0` <br> `(x^(2)+3x-4)/(x)lt0` <br> `((x+4)(x-1))/(x)lt0` <br> `x in (-oo,-4)cup(0,1)` <br> `a=-4, b=0, c=1`Transcript

Time | Transcript |
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00:00 - 00:59 | Hawa question is let solution of inequality this is minus infinity to a union B com Aasai than OK so the given equation is 16 power 1 by X upon to power x + 3 is greater than one ok so 16 can be written as to power phosphate and right to power 4 X upon 2 power x + 3 is greater than zero sorry one so this is not zero this is one ok so I can write it was so if we have a power X upon A power why so I can write it has a power x minus 5 by using this property I can write to power 4 by x minus x minus 3 is greater than one ok and it can be written as |

01:00 - 01:59 | power 4 x minus x minus 3 is greater than 2 power 0 ok so this function is only greater than when this function is greater than 2 power 0 OK three bases are same then power should also be greater than 0 0 so I can write 4 by x minus x minus 3 is greater than zero ok so on taking LCM that is X and on the numerator I can write 4 - x square - 3 x is greater than zero so I can take - as common OK - is common and eliminate it so I can write here X square + 3 x minus 4 upon X is less than zero ok less than zero from here I can write from where I can write X square + 3 x minus 4 |

02:00 - 02:59 | s i x square + 4 x minus x minus 4 upon X is less than zero from here I can write X Into X + 4 minus 1 into X + 4 OK upon X is less than zero from here I can write ok so from here I can write X + 4 into x minus 1 upon X ok upon X is less than zero so I have to draw the number line for solving this so this is my number line and have to locate the points on this function can be zero that is minus 40 and one ok so I put all the brackets = 20 ok so after one if I put more than one letter assume it to be to so this two plus 462 -1 is |

03:00 - 03:59 | latest to solid positive so this value is positive after 30 alternative to change the send positive negative here it is positive here it is negative ok Sabhi aap to take negative value only ok so this interval and this interval ok so from here I can say that X belongs to minus infinity 2 - 4 Union 021 ok so our is equals to a is equals to minus aur b is equals to zero equals to 1 again on comparing with the given sets ok so our equals to minus 4 so if I put in first equation first equation as -4 so that is minus 4 x square + 20 + 9 |

04:00 - 04:59 | that is 16 + 9 x 25 shops and one is correct similarly a + b + c option to is minus 40 plus one ok so this value is -3 that is less than 0 - 3 is less than zero so this option is wrong this option is correct and the third option is third option is a square that is minus 4 y square + 0 + 1 square that is 16 + 1 is equal to 17 this is also write the answer of this given question ok so thank you |

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**Modulus; signum; greatest integer and fractional part function**

**representation of function**

**Physical interpretation**

**Domain codomain and range of function**

**Graph of function: Vertical line test**

**Identity function**

**Explain Constant function with graph**

**Modulus function and properties**

**Greatest integer function and properties**